1.

Consider the following cell reaction: Fe_((s))+O_(2(g))+4H_((aq))^(+)to2Fe_((aq))^(2+)+2H_(2)O_((l)) E^(@)=1.67V At[Fe^(2+)]=10^(-3)M,P_((O_(2)))^(0)=0.1atm and pH=3, the cell potential at 25^(@)C is

Answer»

<P>1.47V
1.77V
1.87V
1.57V

Solution :`E=E^(o)-(0.059)/(4)"log"([Fe^(2+)]^(2))/([H^(+)]^(4)P_(O_(2)))`
`=1.67-(0.06)/(4)"log"((10^(-3))^(2))/((10^(-3))^(4)xx0.1)=1.67-(0.03)/(2)"log"10^(7)`
`=1.67-(0.03)/(2)xx7=1.67-0.105=1.565=1.57V`


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