Consider the following circuit. Find the power dissipation of the transistor given that the diode breakdown voltage is 5V, R1=20kΩ, R2=100kΩ, R3=200kΩ, R4=10Ω. The source voltage VS=20V.(a) 12.12W(b) 9.375W(c) 9.27W(d) 10.575WI have been asked this question in a job interview.This key question is from Voltage Regulators in chapter Regulators of Analog Circuits

Consider the following circuit. Find the power dissipation of the tran

1.	Consider the following circuit. Find the power dissipation of the transistor given that the diode breakdown voltage is 5V, R1=20kΩ, R2=100kΩ, R3=200kΩ, R4=10Ω. The source voltage VS=20V.(a) 12.12W(b) 9.375W(c) 9.27W(d) 10.575WI have been asked this question in a job interview.This key question is from Voltage Regulators in chapter Regulators of Analog Circuits
Answer» CORRECT ANSWER is (b) 9.375W For explanation I would say: Power DISSIPATION = VCE x IC VCE = VC – VE = VS – VOUT = 20-5(1+R2/R3) = 20-5×3/2 = 20-7.5 = 12.5V IC ≈ IE = load current, since R2 and R3 are greater than the load, so most current flows through the load. IL = VOUT/10 = 0.75A P = 12.5 x 0.75 = 9.375W.

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