InterviewSolution
Saved Bookmarks
| 1. |
Consider the following circuit. IDSS = 2mA, VDD = 30V. Find R, given that VP = – 2V.(a) 10kΩ(b) 4kΩ(c) 2kΩ(d) 5kΩThis question was addressed to me in an interview for job.My question is taken from Biasing of JFET and MOSFET in section FET Amplifiers of Analog Circuits |
|
Answer» CORRECT choice is (B) 4kΩ Easy EXPLANATION: IDSS = 2mA IDS = (VDD – 15)/50k = 0.3mA VGS = VP[1 – \(\sqrt{\frac{I_{DS}}{D_{SS}}}\)] VGS = -2 x (1 – \(\sqrt{.15}\)) = – 1.22V Thus, VGS + IDS x (R) = 0 R = 1.22/0.3mA = 4kΩ. |
|