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Consider the following circuit. Process transconductance parameter = 0.50 mA/V^2, W/L=1, Threshold voltage = 3V, VDD = 20V. Find the operating point of circuit.(a) 20V, 25mA(b) 13V, 22mA(c) 12.72V, 23.61mA(d) 20V, 23.61mAThe question was asked by my school teacher while I was bunking the class.Question is taken from Biasing of JFET and MOSFET topic in chapter FET Amplifiers of Analog Circuits

Answer»

Right OPTION is (C) 12.72V, 23.61mA

Explanation: IDS = [k’W/L(VGS – VT)^2]/2

VGS = 20 X 35/55 = 12.72 V

IDS = 0.25 (9.72)^2

IDS = 23.61 mA.



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