1.

Consider the following complex ions, P, Q and R P=[FeF_(6)]^(3-), Q=[V(H_(2)O)_(6)]^(2+) and R=[Fe(H_(2)O)_(6)]^(2+) The correct order of the complex ions, according to their spin only magnetic moment (in B.M.) is

Answer»

`RltQltP`
`QltRltP`
`RltPltQ`
`QltPltR`

SOLUTION :`P=[FeF_(6)]^(3-)` has `Fe^(3+)`, i.e., `3d^(5)` (5 unpaired electron)
`Q=[V(H_(2)O)_(6)]^(2+)` has `V^(2+)`, i.e., `3d^(3)` (3 unpaired electrons)
`R=Fe(H_(2)O)_(6)]^(2+)` has `Fe^(2+)`, i.e., `3d^(6)` (4 unpaired electrons)
Hence, the order of spin only magnetic MOMENT is `QltRltP`.


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