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Consider the following covalent compounds in their solid state and find the value of expression (X+Y+Z). N_(2)O_(5),Cl_(2)O_(6),PC l_(),I_(2)Cl_(6),XeF_(6),PB r_(5) Where X=total number of compounds in which central atom of cationic or anionic part is sp^(3) hybridized. Y=Total number of compounds having 90^(@) bond angle either in cationic or anionic part. Z=Total number of compounds having 109^(@)28' bond angle either in cationic or anionic part. |
Answer» x=1+1+1+1=4 y=1+1=2 z=1+1+1=3 x+y+z=4+2+3=9 |
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