1.

Consider the following electrode potentials{:(,Mg^(+2)+2e^(-)toMg,,,E^(0)=-2.37V),(,V^(+2)+2e^(-)toV,,,E^(0)=-1.18V),(,Cu^(+2)e^(-)toCu^(+),,,E^(0)=0.15V):} Which of the following reactions will proceed from left to right spontaneously ?

Answer»

`MG^(+2)+VtoMg+V^(2+)`
`Mg^(+2)+2CU^(+)toMg+2Cu^(+2)`
`V^(+2)+2Cu^(+)toV+2Cu^(+2)`
`V+2Cu^(+2)toV^(2)+2Cu^(+)`

ANSWER :D


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