1.

Consider the following half cell reactions : Mn^(2+) + 2e^(-) to Mn E^(@) = -1.18 V Mn^(2+) to Mn^(3+) + e^(-)E^(@0 = -1. 51 V The E^@ for the reaction 3Mn^(2+) to Mn + 2Mn^(3+), and the possibility of the forwad reactions are respectively

Answer»

2.69V and spontaneous
`-2.69` and non spotaneous
0.33V and Spontaneous
4.18 V and non spontaneous

Solution :`Mn^(2+) + 2E^(-) to Mn (E_("Red")^(@)) = 1.18 V`
`2[Mn^(2+) + e^(-)] (E_("ox")^(@)) = -151 V`
`3Mn^(2+) to Mn^(3+) + 2 Mn^(3+) E_("cell")^(@)= ?`
`E_("cell")^(@) = (E_("ox")^@) + (E_("Red")^@)`
`= -1.51 - 1.18` and non spontaneous
`=2.69 V`
SINCE `E^@` is -ve `DELTAG` is +ve and the given forward cell reaction is non-spotaneous.


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