Consider the following hypothetical equilibrium `2B(g)hArrB_(2)(g)` If `d` is observed vapour density and `D` is theoretical vapour density, then degree of association `(alpha)` will beA. `alpha=((D-d)/(d))`B. `alpha=(2D-d)/(D)`C. `alpha=2-(2D)/(d)`D. `alpha=(2D)/(D-d)`

Consider the following hypothetical equilibrium `2B(g)hArrB_(2)(g)` If

1.	Consider the following hypothetical equilibrium `2B(g)hArrB_(2)(g)` If `d` is observed vapour density and `D` is theoretical vapour density, then degree of association `(alpha)` will beA. `alpha=((D-d)/(d))`B. `alpha=(2D-d)/(D)`C. `alpha=2-(2D)/(d)`D. `alpha=(2D)/(D-d)`
Answer» Correct Answer - C

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Consider the following hypothetical equilibrium `2B(g)hArrB_(2)(g)` If `d` is observed vapour density and `D` is theoretical vapour density, then degree of association `(alpha)` will beA. `alpha=((D-d)/(d))`B. `alpha=(2D-d)/(D)`C. `alpha=2-(2D)/(d)`D. `alpha=(2D)/(D-d)`

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