1.

Consider the following nuclear reaction : ""_(92)^(238)Mto""_(y)^(x)N+2""_(2)^(4)He ""_(y)^(x)Nto""_(B)^(A)L+2beta^(+) The number of neutrons in the element L is

Answer»

140
144
142
146

Solution :`""_(92)^(234)Mto""_(88)^(230)N+2""_(2)^(4)He`
`""_(88)^(230)Nto_(86)^(230)L+2""_(+1)overset(0)E`
No. of neutrons =230-86=144


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