1.

Consider the following nuclear reactions ._(92)^(238)M rarr ._(X)^(Y)N + 2alpha, ._(X)^(Y)N rarr ._(B)^(A)L + 2beta The number of neutrons in the element L is

Answer»

142
144
140
146

Solution :Nuclear reaction
`._(92)^(238)M RARR ._(X)^(Y)N + 2 ALPHA (2 xx ._(2)^(4)He) or ._(88)^(230)N`
`._(88)^(230)N rarr ._(B)^(A)L + 2 ._(+1)^(0)e or ._(90)^(23)L`
`.:` No of NEUTRON in L `= 230 - 86 = 140`


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