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Consider the following program fragment for reversing the digits in a given integer to obtain a new integer. Let n = D1D2…Dmint n, rev;rev = 0;while (n > 0){rev = rev*10 + n%10;n = n/10;}The loop invariant condition at the end of the ith iteration is: (GATE CS 2004)(A) n = D1D2….Dm-i and rev = DmDm-1…Dm-i+1(B) n = Dm-i+1…Dm-1Dm and rev = Dm-1….D2D1(C) n != rev(D) n = D1D2….Dm and rev = DmDm-1…D2D1 |
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