InterviewSolution
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InterviewSolution
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Consider the following reaction: `2NaN_(3)(s) rarr 2Na(s) +3N_(2)(g)` The enthalpy change for this reaction at `1atm` is equal to:A. `-2Delta_(f)H^(Theta) [NaN_(3)(s)]`B. `+2Delta_(f)H^(Theta)[NaN_(3)(s)]`C. `3Delta_(f)H^(Theta)[N_(2)(s)+2Delta_(f)H^(Theta)(Na(s)]`D. `-Delta_(f)H^(Theta)[NaN_(3)(s)]` |
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Answer» `Delta_(f)H = DeltaH_(P) - DeltaH_(R)` `[{:("Enthalpy of elements in their"),("stable state is assumed to be"),("zero".):}]` `=(2 xx H_(Na) +3 xx H_(N_(2))) -2H_(NaN_(3))` `=(2 xx 0+3 xx0) - 2H_(NaN_(3))` `=- 2H_(NaN_(3))` |
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