1.

Consider the following reaction, 5H_2O_2+x CIO_2+2OH^(-)toxCI^(-)+yO_2+H_2 O the reactinis balancedif

Answer»

`x=5,y=2`
`x=2 ,y=5`
`x=4 ,y=10`
`x=5,y=5`

Solution :thetwohalfreactionsare ,
oxidation ` H_2 overset(-1)O_2tooverset(0) O_2`
REDUCTION: `overset(+4)CIO_2to CI^(-)`
to balanceO.NinEqn(I ) add`2e^(-)` toR.H.S we have
`H_2O_2to O_2 +2e^(-)`
totalbalancechargeadd`2 OH^(-)to O_2 + 2e^-`
tobalanceH and O atoms add2 `H_2O`to the R.H.Swehave
` H_2O_2+ 2OH^(- )to O_2+2H_2 O + 2e^(-)`
thisis theoxidationhalfequation
tobalanceO.Nin EQN(ii ) add`5e^(-)`to L.H.Swe have
`CIO_2+ 5E^( -)to CI^(-)`
to balancechangeadd4 `OH^(- ) ` to theR.H.Swe have
`CIO_2+ 5e^(- )to CI+ 4 OH`
to balanceO ANDH atomsAdd2 `H_2O` toL.H.Swe have`CIO_2+ 2 H_2O+ 5 e^(- )to CI^( -)+ 4 OH^(-)`
thisis thebalanced reductionhalfequation
tocancel the numberof electronslostin eqn(v )andgainedin Eqn(viii )multiplyEqn(v )by5 and Eqn(viii )by2and addwe have

thusx thecoefficientof `CIO_2 `is 2whiley thecoefficientof` CI^(-)`is 5


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