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Consider the following reaction : (A) H^(+)(aq) + OH^(-)(aq) = H_(2)O(l): Delta H = -X_(1) kJ mol^(-1) (B) H_(2)(g) + (1)/(2) O_(2)(g) = H_(2)O(l): Delta H = -X_(2) kJ mol^(-1) ( C ) CO_(2)(g) + H_(2)(g) = CO(g) + H_(2)O(l): Delta H = -X_(3) kJ mol^(-1) (D) C_(2)H_(2)(g) + (5)/(2) O_(2)(g) = 2CO_(2) + H_(2)O(l): Delta H = +X_(4) kJ mol^(-1) Enthalpy of formation of H_(2)O(l) is : |
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Answer» `+ X_(1) KJ mol^(-1)` `H_(2)(g) + (1)/(2) O_(2)(g) = H_(2)O(l)` :. `Delta H = - X_(2) kJ mol^(-1)` |
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