Consider the following reaction at certain temperature : H_(2) (g) + Cl_(2) (g) hArr 2HCl (g) The mixing of 1 mol of H_(2) with 4 moles of Cl_(2) from x moles of HCl at equilibrium. If we add 5 moles of H_(2) at equilibrium then another 2x moles of HCl are produced. Then find K_("eq") for above reaction.

Consider the following reaction at certain temperature : H_(2) (g) +

1.	Consider the following reaction at certain temperature : H_(2) (g) + Cl_(2) (g) hArr 2HCl (g) The mixing of 1 mol of H_(2) with 4 moles of Cl_(2) from x moles of HCl at equilibrium. If we add 5 moles of H_(2) at equilibrium then another 2x moles of HCl are produced. Then find K_("eq") for above reaction.
Answer» Solution :`{:(,H_(2) (g),+,Cl_(2) (g),hArr,2HCl (g),,),("INITIALLY",1,,4,,-,,),("Equilibrium",1 - (X)/(2),,4 - (x)/(2),,x,,),("New Equilibrium",6 - (3x)/(2),,4 - (3x)/(2),,3x,["After adding 5 moles of" H_(2)],):}` `K_(C) = (x^(2))/((1 - (x)/(2))(4 - (x)/(2))) = ((3x)^(2))/((4 - (3x)/(2)) (6 - (3x)/(2)))` `x = 1.6` `K_(eq) = (1.6 xx 1.6)/((1 - (1.6)/(2))(4 - (1.6)/(2)))` `K_(eq) = 4`