1.

Consider the following reaction RONa+H_(2)C to ROH+NaOH ROH+NaNH_(2) to RONa+NH_(3) Predict which of the following order reagarding base strength is correct.

Answer»

`OH^(-)LT NH_(2)^(-) lt RO^(-)`
`NH_(2)^(-)lt OH^(-) lt RO\^(-)
`OH^(-)lt RO^(-) lt NH_(2)^(-)
`RO^(-)lt NH_(2)^(-) lt OH^(-)

Solution :`R-overset(-)(Ona^(+)) +H_(2)O to ROH+NaOH`
`ROH+NaNH_(2) to RONa+NH_(3)`
Since the reaction is favoured in forward DIRECTION, `RO^(-)` is stronger BASE than `OH^(-)`. According to the second reaction `NH_(2)^(-)` is stronger than `RO^(-) as NH_(2)^(-) "forms" NH_(3)`. The order of basic strength if `OH^(-) lt RO^(-) lt NH_(2)^(-)` .


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