1.

Consider the following relations for emf of a electrochemical cell (1) emf of cell=(Oxidation potential of anode)-(Reduction potential of cathode) (2) emf of cell=(Oxidation potential of anode)+(Reduction potential of cathode) (3) emf of cell=(Reduction potential of anode)-(Reduction potential of cathode). (4) emf of cell=(Oxidation potential of anode)-(Oxidation potential of cathode) Which of the above relations are correct

Answer»

3 and 1
1 and 2
3 and 4
2 and 4

Solution :`E_(cell)=E_("cathode (red)")^(0)-E_("anode (Red)")^(0)` or `E_(cell)=E_("cathode (red)")-E_("anode (OXID)")^(0)`
or `C_(cell)=E_("anode (oxid)")^(0)-E_("cathode (oxid)")^(0)`


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