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Consider the following relations for `emf` of a electrochemical cell (i) emf of cell = (Oxidation potential of anode)-(Reduction potential of cathode) (ii) emf of cell = (Oxidation potential of anode)+(Reduction potential of cathode) (iii) emf of cell = (Reduction potential of anode)+(Reduction potential of cathode) (iv) emf of cell = (Oxidation potential of anode)-(Oxidation potential of cathode) Which of the above realtions are correct?A. (iii) and (iv)B. (i) and (ii)C. (iii) and (iv)D. (ii) and (iv) |
Answer» Correct Answer - D EMF of a cell = Reduction potential of cathode - Reduction potential of anode = Reduction potential of cathode + Oxidation of anode = Oxidation potential of anode - Oxidation potential of cathode |
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