1.

Consider the following statements: (a) The pH of a mixture containing 400 mL of 0.1 MH_(2)SO_(4) and 400 mL of 0.1 M NaOH will be approximately 1.3. (b) Ionic product of water is termperature dependent. ( c) A monobasic acid with K_(a) = 10^(-5) has a pH =5. The degree of dissociation of this acid is 50% (d) The Le Chatelier's principle is not applicable to common-ion effect.

Answer»

a and b
a,b and c
b and c
a,b and d

Solution :`underset("40 m mol excess")(H_(2)SO_(4)) + underset("40 m mol limiting reagent")(2NaOH) to Na_(2)SO_(4) + 2H_(2)O`
After reaction
`"20 m mol020 m mol40 m mol"`
Total VOLUME = 400+400 = 800 mmol
Number of moles of `H_(2)SO_(4)=20` m mol
Number of moles of `H^(+)` ion = `2 xx 20` m mol = 40 m mol
`[H^(+)] = 40/800 = 0.05` M
`pH=-logH^(+)] =-log(0.05) =2-log 5=2-0.7 = 1.3`
pH=1.3
(B) `K_(omega) = [H^(+)][OH^(-)]`
As T increases, `K_(omega)` also increases
(c ) pH=5 and `K_(4)=10^(-5)`
`rArr -log[H^(+)]=5`
`[H^(+)]=10^(-5)`
Weak monobasic acid 'HA' having concentration 'C'
`{:(,HA(aq), H^(+)(aq)+,A^(-1)(aq)),("At t=0",C,0,0),("At equilibrium",C-Calpha,Calpha,Calpha):}`
`K_(a) =([H^(+)][A^(-1)])/([HA]) =(Calpha)/(C(1-alpha))`
`alpha to` DEGREE of dissociation
`THEREFORE K_(a) = (Calpha^(2))/(1-alpha) = 10^(-5)`...........(1) (given)
`[H^(+)]= Calpha = 10^(-5)`.............(2)
From EQUATION (1) & (2)
`alpha/(1-alpha)=1 rArr alpha=1-alpha`
`alpha = 1/2`
`% alpha = 1/2 xx 100 = 50%`


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