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Consider the following statements and arrange in the order of true/false as given in the codes. S_1:From solution containing coppe (+2) and zinc )(+2) ions, copper can be selectively precipitated using sodium sulphide. S_2:Amongst Ca^(2+),Al^(3+),Bi^(3+), and Mg^(2+) the NH_4Cl and aqueous ammonia will precipitate only Al^(3+) as its hydroxide. S_3:Sodium chloride on reaction with conc. H_2SO_4 in presence of MnO_2 liberates a greenish yellow gas. S_4:The formation of brown precipitate on reaction with alkaline K_2[HgI_4] indicates the presence of NH_4^(+) |
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Answer» T T T T `S_2`:`Ca^(2+)` and `Mg^(2+)` will not precipitate as `K_(sp)` of their hydroxides are very high. `BI^(3+)+3(OH^-)toBi(OH)_3 darr` (White) `Al^(3+)+3(OH^-)toAl(OH)_3darr` (white) `S_3:2Cl^(-)+MnO_2+H_2SO_4 +2H^(+)toMn^(2+)+SO_4^(2-)+2H_2O+Cl_2 UARR` (greenish yellow) ` (##RES_INO_RK_JA_C08_E01_1061_S01.png" width="80%"> |
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