1.

Consider the following statements and arrange in the order of true /false as given in the codes. S_1:In I Cl_2^(-), CIF_3 and TeCl_4 the number of lone pairs of electrons on central atoms are 3,2 and 1 respectively. S_2:Amongest NO, C_2, O_2^(-) , He_2^+, the increasing order of bond dissociation energies of He_2^+ lt O_2^(-) lt C_2 lt NO. S_3:Amongst CO, CO_2, CO_3^(2-),CH_3OH, the correct order from the weakest to the strongest carbon - oxygen bond is CH_3OH lt CO_3^(2-) lt CO_2 lt CO S_4:The hybridisation of boron in Cl_2BBCl_2 is the same which nitrogen has in CINO molecules.

Answer»

T T TT
T T TF
T F T F
F T T F

Solution :(A)`S_1`:
`S_2`:`He_2^+` bond order =`(2-1)/2=1/2 ,O_2^(-)` bond order =`(10-7)/2=1.5`
`C_2` bond order =`(8-4)/2=2`, NO bond order =`(10-5)/2=2.5`
Bond order `PROP` bond dissociation ENERGY
`S_3:C-O =1.43Å , C=O 1.23 Å , C-=O 1.09 Å`
`CO:Coverset to = O`, partial triple bond character , bond length is inter mediate of C=O and C= O bonds `CO_2`, O=C=O , double bond length

`CH_3OH, H-undersetunderset(H)(|)oversetoverset(H)(|)C-O-H` , single bond length .
`S_4`:


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