Consider the following statements and arrange in the order of true/false as given in the codes. S_1:Na_2O_2ltMgOltZnOltP_4O_(10):Acidic property. S_2:NaltSigtMgltAl:First ionisation energy. S_3:FgtClgtBr:Electron affinity.

Consider the following statements and arrange in the order of true/fal

1.	Consider the following statements and arrange in the order of true/false as given in the codes. S_1:Na_2O_2ltMgOltZnOltP_4O_(10):Acidic property. S_2:NaltSigtMgltAl:First ionisation energy. S_3:FgtClgtBr:Electron affinity.
Answer» TTT TTF TFF TFT Solution :`S_1:Na_2O_2ltMgOltZnOlt P_4O_10`: as non-metallic character increases the acidic character increases `MgO,Na_2O` are basic: ZnO AMPHOTERIC and `P_4O_10` acidic. `S_2:NaltSigtAlltMg:Mg` has higher than Na DUE to small size and higher nuclear charge .Mg has highest than Al because of `ns^2` configuration (has extra stability and high electron penetration power of s-subshell electrons) and Si has highest than Al because of higher nuclear charge and small size.`IE_1 :Na=496,Al=577,Mg=737 and Si=786` kJ/mole `S_3:`There is more interelectronic REPULSION in 2p-subshell of fluorine than CHLORINE (3p), So extra electron will be ADDED easily in 3p-subshell of chlorine as compared to 2p-subshell of fluorine.Down the group electron affinity values generally decreases with increasing atomic number due to increase in atomic size. So`ClgtFgtBr`