Consider the following statements - (i) At same P, if V vs T graph is draw for sam e mass of the two idea gaes, then the heavier has will have a heighter slope. (ii) Intercept of log V vs T graph should always be posiive. (iii) Graph of V^(2) vs (1)/(T^(2)) for fixes amount of an ideal gas at constant pressure will be a parabola.

Consider the following statements - (i) At same P, if V vs T graph is

1.	Consider the following statements - (i) At same P, if V vs T graph is draw for sam e mass of the two idea gaes, then the heavier has will have a heighter slope. (ii) Intercept of log V vs T graph should always be posiive. (iii) Graph of V^(2) vs (1)/(T^(2)) for fixes amount of an ideal gas at constant pressure will be a parabola.
Answer» FTF FFT FFF TTF Solution :(i) `M_(1) gt M_(2)` (GAS is HEAVIER) `n_(1) gt n_(2)` `{:(V = n_(1) RT,V = n_(2) RT,),("P","P",),("Slope","Slope",):}` Heavier gas has lower slope (ii) PV = NRT `V = (nR)/(P) T` logV = log `(nR)/(P) +` log T InterceptC = log `(nR)/(P)` (Can be POSTIVE and negative)