1.

Consider the follwing nuclear reactions: ._(92)^(238) M rarr ._(y)^(x)N + 2 ._(2)He^(4) ._(y)^(x)N rarr ._(B)^(A)L + 2beta^(+)

Answer»

142
144
140
146

Solution :`._(92)^(238)M rarr _(Y)^(X)N+2._(2)^(4)He`
Applying mass number balance & nuclear CHARGE balance
92=y+4 `""` y=88
238=x+8 ` ""` x=230
`._(Y)^(X)N rarr _(B) ^(A) L+2 beta^(+) (._(+1)e^(0))`
Applying mass number balance & nuclear charge balance
230=A+0 `""` A=230
88=B+2 ` "" ` B=86
No. of neutrons in ELEMENT L is 230-86=144.


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