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Consider the heterogeneous equilibrium in a closed container `NH_(4)HS (s)hArrNH_(3) (g) + H_(2)S(g)` If more `NH_(4)Hs` is added to the equilibriumA. Partial pressure of `NH_(3)` increasesB. Partial pressure of `H_(2)S` increasesC. Total pressure in the container increasesD. No effect on partial pressure of `NH_(3)` and `H_(2)S` |
Answer» Correct Answer - D `NH_(4)HS (s)hArrNH_(3)(g) + H_(2)S(g)` `K_(p)= NH_(3)(g)xxH_(2)S(g)` Partial pressure of `NH_(3)` and `H_(2)O` do not affect `NH_(4)HS(s)` because `NH_(4)HS(s)` is solid for solid active mass unity. |
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