1.

Consider the isoelectronic series : K^(+), S^(2-) , Cl^(-) and Ca^(2+), the radii of the ions decrease as

Answer»

`Ca^(2+) gt K^(+) gt CL^(-) gt S^(2-)`
`Cl^(-) gt S^(2-) gtK^(+) gt Ca^(2+)`
`S^(2-) gt Cl^(-) gt K^(+) gt Ca^(2+)`
`K^(+) gt Ca^(2+) gt S^(2-)gt Cl^(-)`

Solution :Amongest isoelectronic ions, ionic , radii of ANIONS is more than that of cations. Further size of the anion INCREASES with increases with INCREASE in -ve charge and size of cation decreases with increase +ve charge.


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