1.

Consider the junction diode as ideal. The value of current flowing through AB is

Answer»

OA
`10^(-2)A`
`10^(-1)A`
`10^(-3)A`

Solution :As, `V_(A) -V_(B)=IR, so 4-(-6)=Ixx1000`
or `I=10/1000=10^(-2)A`


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