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Consider the network as shown in Fig. Current is supplied to the network by two batteries as shown. Find the values of currents I_(1), I_(2), I_(3). The direction of the currents are as indicated by the arrows. |
Answer» SOLUTION : Applying Kirchhoff.s 1st law to junction C, we GET `I_(1)+I_(2)-I_(3)=0"….(1)"` Applying Kirchhoff.s Iind law to the closed meshes ACDA and BCDB, we get `-5I_(1)-2I_(3)+12=0 rArr 5I_(1)+2I_(3)=12"...(2)"` `-3I_(1)-2I_(3)+6=0 rArr 3I_(1)+2I_(3)=6"....(3)"` On solving , `I_(1)=1.548A`. `I_(2)=0.58A and I_(3)=I_(1)+I_(2)=2.3128A`. |
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