Consider the reaction 2Al (g) + 3Cl_(2) (g) rArr 2Al Cl_(3) (g). The a – InterviewSolution

1.	Consider the reaction 2Al (g) + 3Cl_(2) (g) rArr 2Al Cl_(3) (g). The approximate volume of chlorine that would react with 324 g of aluminium at STP is :
Answer» 112 L 134 L 260 L 403 L Solution :324 g AL `-= (324)/(27) = 12mol Al -= (12 xx 3)/(2) mol Cl_(2) = 18mol Cl_(2) = -= 18 xx 22.4` It of `Cl_(2)`ats.T.P.= 403.2 lt

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