1.

Consider the reaction : 4 NO_(2 (g)) + O_(2 (g)) to 2 N_(2)O_(5 (g)) , Delta_(r) H = -111 kJ If N_(2) O_(5 (s)) is formed instead of N_(2)O_(5 (g)) in the above reaction , the Delta_(r)H value will be : (given , Delta H of sublimation for N_(2) O_(5) is 54 kJ mol^(-1))

Answer»

`+54` KJ
`+ 219` kJ
`-219` kJ
`-165 ` kJ

Answer :C


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