1.

Consider the reaction at 300 K H_(2)(g)+Cl_(2)(g) to 2HCl(g)""DeltaH = - 185kJ//molCalculate DeltaU if 3mole of H_(2)completely react with 3 mo,le f of Cl_(2) tofrom HCl.

Answer»

0
`-185 kJ`
`555kJ`
None of these

Solution :`Deltan_(g) = 0rArr DeltaH= DELTAU = - 185 kJ//"MOLE"`
For three moles= - `185 XX 3 = -555 `


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