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    				| 1. | Consider the reaction at `300K` `C_(6)H_(6)(l)+(15)/(2)O_(2)(g)rarr 6CO_(2)(g)+3H_(2)O(l),DeltaH=-3271`kJ What is `DeltaU` for the combustion of `1.5` mole of benzene at `27^(@)C` ?A. `-3267.25kJ`B. `-4900.88kJ`C. `-4906.5kJ`D. `-3274.75kJ` | 
| Answer» Correct Answer - 2 For 1 mole of combustion of benzene `Deltan=-1.5` `DeltaH^(@)=DeltaU+Deltan_(9)RT` `rArr-3271=DeltaU-(1.5xx8.314xx300)/(1000)` `rArr" "DeltaU=-3267.25xx1.5=-4900.88kJ` | |