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Consider the reaction: `N_(2) + 3H_(2) hArr 2NH_(3)` carried out at constant pressure and temperature. If `DeltaH` and `DeltaU` are change in enthalpy and change in internal energy respectively, then:A. `DeltaH=0`B. `DeltaH=DeltaU`C. `DeltaH lt DeltaU`D. `DeltaH gt DeltaU` |
Answer» Correct Answer - C `DeltaH=DeltaU+DeltanRT` `:. Deltan=2-4=-2` `:. DeltaHlt DeltaU` |
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