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Consider the reaction: `N_(2) + 3H_(2) hArr 2NH_(3)` carried out at constant pressure and temperature. If `DeltaH` and `DeltaU` are change in enthalpy and change in internal energy respectively, then:A. `Delta=0`B. `Delta=DeltaU`C. `DeltaH lt DeltaU`D. `DeltaH gt DeltaU` |
Answer» Correct Answer - C `Deltan_(g)` for this reaction is `-ve` (`Deltan_(g)=-4` if `NH_(3)` is considered as liquid and `Deltan_(g)=-2` if `NH_(3)` is considered as gas) Now `DeltaH=DeltaU+Deltan_(g)RT` `:. DeltaH lt DeltaU` for this reaction. |
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