1.

Consider the reaction :N_(2)+3H_(2)rarr2NH_(3) carried out at constant temperature and pressure. If DeltaH and DeltaU are the enthalpy and internal energy changes for the reactions, which of the following expression is true

Answer»

<P>`DELTAH = 0`
`DeltaH = DeltaU`
`DeltaH LT DeltaU`
`DeltaH gt DeltaU`

Solution :At constant P or T
`DeltaH=DeltaU+DeltanRTimplies Deltan=n_(p)-n_(R)=2-4=-2`
`therefore DeltaHltDeltaU`.


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