1.

Consider the reaction: N_2(g) + 3H_2(g)to2NH_3(g) carried out at constant temperature and pressure. If Delta H and Delta Eare the enthalpy and internal energy changes for the reaction, which of the following expressions is true?

Answer»

`Delta H = 0 `
`Delta H = Delta E`
`Delta H lt Delta E`
`Delta H GT Delta E`

Solution :`N_2(g) + 3H_2(g)to 2NH_3(g)`
` Delta N(g) = 2 -4= -2, Delta H = Delta E + Delta n(g) RT = Delta E - 2RT`
` therefore Delta H lt Delta E`


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