1.

Consider the reaction where K_(p)=0.497at 500K. PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g)) If the thre gases are mixed in a rigid containeer so that the partial pressure of each gas is initially 1 atm, which is true

Answer»

<P>More `PCl_(5)` will be produced
More `PCl_(3)` will be proudced
Equlibrium will be ESTABLISHED when `50%` REACTION is complete
None of the above

Solution :`Q_(p)=(pPCl_(3)xxpCl_(2))/(pPCl_(5))=(1atmxx1atm)/(1atm)=1atm`
Since, `Q_(p)gtK_(p),` the equlibrium shifts towards left.


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