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Consider the sequence `1,2,2,3,3,3,"……",` where n occurs n times that occuts as 201th rerms isA. 61B. 62C. 63D. 64 |
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Answer» Correct Answer - C The last 4 occurs as `1+2+3+4+=10th` term. The last n occurs as `((n(n+1))/(2))^(th)` term, the last 62 occurs as `((63xx63)/(2))^(th)=1953rd` term and the last 63 occurs as `((64xx64)/(2))^(th)=2016th` term. `:. 63` occurs from 1954th term to 2016th term. Hence, `(2011)^(th)` term os 63. |
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