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Consider the situation of the previous problem. A charge of 2.0xx 10 ^(-4) C is moved from the point A to the point B. find the change in electrical potential energy U_B-U_A for the cases (a) , (b) and ( c ). |
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Answer» SOLUTION :(a) the electric field is ALONG x DIRECTION Thus potential DIFFERENCE between `(0,0) and (4,2) is, ` ` dV=-edx=-20xx4 ` ` =-80volt ` ` Potential energy (U_B-U_A) between the points=dVxxq ` ` =-80xx-2.0xx10^-4 ` ` =160xx10^-4=0.016J ` ` (b) A=(4m,2m),B=(6m,5m) ` ` dV=-exxdx=-20xx2=-40v ` ` Potential energy (U_B-U_A) between the points=dVxxq ` ` =-40xx(-2xx10^-4) ` ` 80xx10^-4=0.008J ` ` (c) A=(0,0) B=(6m,5m) ` ` dV=-E.dx=-20xx6` ` -120V ` ` potential energy (U_B-U_A) between the points A and B=dVxxq ` ` =-120xx(-2xx10^-4) ` ` 240xx10^-4=0.024J ` |
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