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Consider the situation shown in figure. A plane mirror is fixed at a height h above the bottom of a beaker containing water (refractive index `mu`) up of a bottom formed by the mirror. |
Answer» The bottom of the beker appears to be shifted up by a distance `/_ =(1-1/mu)d` Thus, the apparent distance of the bottom from the mirror is `h/_ =h-(1-1/mu)d=h-d+d/mu`. The image is formed behind the mirror at a distance `h-d+d/mu` |
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