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Consider the situtaion shown in figure. Find distance of image of O from eye E. |
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Answer» Solution :Shift by (1), `t_(1)(1-1//mu_(1))=3(1-2//3)=1cm` Shift by (2), `t_(2)(1-1//mu_(2))=4(1-4)=3cm` Shift by (3), `t_(3)(1-1//mu_(3))=6(1-1//3)=4 cm` IMAGE of O is formed at I. OI=8 cm `rArrEO=6+6+1+4+1+3+6=27 cm` EI=EO-OI=27-8=19 cm |
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