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Consider the spectral line resulting from the transition `n = 2 rarr n = 1 ` in the atoms and ions given . The shortest wavelength is produced byA. hydrogen atomB. deuterium atomC. singly ionization heliumD. doubly ionized lithium |
Answer» Correct Answer - D We know that `(1)/(lambda) = R z^(2) [(1)/(n_(2)^(2)) - (1)/(n_(1)^(2))] implies (1)/(lambda) prop z^(2)` `lambda` is shortest when `1//lambda` is i.e., when `z` is big `z` is highest for lithum. |
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