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Consider the two lines `x+y+1=0` and `3x+2y+1=0` What is the equation of the line passing through the point of intersection of the given lines and parallel to x-axis ?A. `y+1=0`B. `y-1=0`C. `y-2=0`D. `y+2=0`

Answer» Correct Answer - D
Equations of lines
`x+y+1=0`
`3x+2y+1=0`
`{:(3x+3y+3=0),(3x+2y+1=0),("- - - -"),(bar(" y = -2 ")),(" "x=1):}`
Points of intersection (1, -2)
Equation of x-axis
`y=0`
Line parallel to x axis is
`y=k`
If this line passes through (1, -2) then
`k=-2`
`implies y=-2`
`implies y+2=0`
Equation of line passing through (1, -2) and parallel to x-axis is
`y+2=0`


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