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If the straight lines x - 2y=0 and kx + y=1 intersectsat the point (1,1/2) then what is the value of k?A. 1B. 2C. `1//2`D. `-1//2` |
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Answer» Correct Answer - C Since. The straight lines `x-2y=0` and `kx+y=1` intersect at the point `(1, 1/2)` `:.` The point `(1, 1/2)` satisfies the equation `kx+y=1` `:.` Put `x=1`, and `y=1/2` in `eq^(n) kx+y=1`, we get `k.1+1/2 = 1 implies k=1/2` |
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