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Consider the two lines `x+y+1=0` and `3x+2y+1=0` What is the equation of the line passing through the point of intersection of the given lines and parallel to y-axis ?A. `x+1=0`B. `x-1=0`C. `x-2=0`D. `x+2=0`

Answer» Correct Answer - B
Equations of lines
`x+y+1=0`
`3x+2y+1=0`
`{:(3x+3y+3=0),(3x+2y+1=0),("- - - -"),(bar(" y = -2 ")),(" "x=1):}`
Points of intersection (1, -2)
Equation of y-axis
`x=0`
Equation of line parallel to y-axis is
`x=k`
If this line passes through (1, -2 then)
`x=1`
Hence equation of line which passes through point of intersection of given line (1, -2) and parallel to y-axis `x=1`
`implies x-1=0`


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