Consider the value of all four quantum number for last electron and spin multiplicity (2s+1) for givenn two element 'X' and 'Y' in their ground state: {:(,n,,l,m,s,|2s+1|),(X:,2,0,0,+1//2,1),(Y:,2,1,-1,-1//2,4):} The according to given information the correct statement is:

Consider the value of all four quantum number for last electron and sp

1.	Consider the value of all four quantum number for last electron and spin multiplicity (2s+1) for givenn two element 'X' and 'Y' in their ground state: {:(,n,,l,m,s,\|2s+1\|),(X:,2,0,0,+1//2,1),(Y:,2,1,-1,-1//2,4):} The according to given information the correct statement is:
Answer» The BOND angle `(H-Y-H)` of possible hydride of element Y is less than `190"28'` The possible halide of 'X' has two vacant p-orbitals on its central atom. Magnetic MOMENT of Y is greater than X X and Y element exhibits only single oxidation are Solution :According to given information `X implies Be and Y implies N` (a0 possible hydride of N is `NH_(3)(H-N-H` bond angle is less than `109"28.`) (b) In `BeX_(2)`, Be has two vacent p-orbirtals (c) Magneti cmoment of N>Be. (number of unpaired `e^(-)` in N>Be) (d) N can exhibits variable oxidation state.