1.

Consider this reaction, 2H_(2)(g)+2NO(g)to N_(2)(g)+2H_(2)O(g) The rate law for this for reaction is rate =k[H_(2)][NO]^(2) . Under what conditions could these Steps represent the mechanism? Step1: 2NOtoN_(2)O_(2) Step2: N_(2)O_(2)+H_(2)to N_(2)O+H_(2)O Step3:N_(2)O+H_(2)to N_(2)+H_(2)O

Answer»

These STEPS cannot be the mechanism under any circumstances.
These steps COULD be the mechanism if Step 1 is the SLOW step.
These step could be the mechanism if Setp2 is the slow step.
These Stepscould be the mechanism if Step 3 is the slow step.

Answer :C


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