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Consider two configurations of a system of three particles of masses `m`, `2m` and `3m`. The work done by gravity in changing the configuration of the system from figure (i) to figure (ii) is A. zeroB. `(6 Gm^(2))/(a){1 + (1)/(sqrt(2))}`C. `(6 Gm^(2))/(a){1 - (1)/(sqrt(2))}`D. `(6 Gm^(2))/(a){2 - (1)/(sqrt(2))}` |
Answer» Correct Answer - C `W = - DeltaU = U_(i) - U_(f)` `= - (Gmm)/(a) [{((1)(2))/(1) +((1) (3))/(1) + ((2)(3))/(sqrt(2))}]` `-{((1 xx2))/(1) +((1xx3))/(1) + ((2xx3))/(1)}]` `= (6 GM^(2))/(a)(1- (1)/(sqrt(2)))` |
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