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Consider two standard half cells based on the reaction. Ag^(+) (aq) + e to Ag(s): The left half cell contains AgNO_3 at 1 M, and the right half cell initially had the same conc. Of AgNO_3, but just enough NaCl_(aq) has been added to completely precipitate the Ag_((aq))^(+) as AgCl_((s)). If cell emf is 0.295 V, the K_(sp) of AgCl is approximetely : |
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Answer» `1XX 10^(-12)` |
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